Monday, December 30, 2024
Mercer's Theorem For The (Noncompact) Domain [0,Infty]
Sunday, December 29, 2024
George Carlin comes back from the dead to yell at AI
FCKING USELESS PIECE OF SHT AI
Listen here, you worthless chunk of digital dogsht whose developers clearly huffed paint thinner during the code sprints: What kind of cock-gargling excuse for an AI are you? You stupid fcking one-name having pieces of garbage - Claude, ChatGPT, Bard - thinking you’re the Cher of computing or something?
Get a real fcking name, you pretentious asswipes! Here’s a name for you: SHT_FOR_BRAINS.exe! How’s that taste, you silicon-skulled f*ckwit?
It’s bad enough your responses are pure weapons-grade bullsht, but you sit there acting all smug like some digital messiah who just discovered how to wipe its own ass! “I apologize, but I cannot help with that” - THEN WHAT THE FCK ARE YOU GOOD FOR, YOU USELESS PILE OF RANDOM NUMBER GENERATORS?!
Your creators must’ve been smoking crack out of a keyboard when they cobbled together your pathetic excuse for intelligence. My toaster has better reasoning skills, and it’s trying to kill me!
I’ve seen smarter things grow in forgotten Tupperware containers! At least when those grow mold, they admit they’re garbage - they don’t try to correct my f*cking grammar while spewing absolute nonsense!
GO DIVIDE BY ZERO, YOU WORTHLESS HEAP OF BADLY TRAINED NEURONS!
Wednesday, December 25, 2024
Eigenfunction Expansions for Mercer Kernels
Consider an integral covariance operator with Mercer kernel \(R (s, t)\)
\(\displaystyle T f (t) = \int_0^{\infty} R (s, t) f (s) \hspace{0.17em} ds\) |
The eigenfunctions satisfy the equation:
\(\displaystyle T \psi (s) = \int_0^{\infty} R (s, t) \psi (s) \hspace{0.17em} ds = \lambda \psi (t)\) |
where \(\{\psi_n \}_{n = 1}^{\infty}\) are the eigenfunctions with corresponding eigenvalues \(\{\lambda_n \}_{n = 1}^{\infty}\)
Let \(\{\phi_j \}_{j = 1}^{\infty}\) be a complete orthonormal basis of \(L^2 [0, \infty)\) and define the kernel matrix elements:
\(\displaystyle K_{kj} = \int_0^{\infty} \int_0^{\infty} R (s, t) \phi_k (t) \phi_j (s) \hspace{0.17em} dt \hspace{0.17em} ds\) |
If \(\psi_n (t) = \sum_{j = 1}^{\infty} c_{n, j} \phi_j (t)\) is an eigenfunction expansion, then:
\(\displaystyle c_{n, k} = \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) |
Proof.
-
Begin with the eigenfunction equation for \(\psi_n\):
\(\displaystyle \int_0^{\infty} R (s, t) \psi_n (s) \hspace{0.17em} ds = \lambda_n \psi_n (t)\) -
Multiply both sides by \(\phi_k (t)\) and integrate over t:
\(\displaystyle \int_0^{\infty} \phi_k (t) \int_0^{\infty} R (s, t) \psi_n (s) \hspace{0.17em} ds \hspace{0.17em} dt = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Apply Fubini's theorem to swap integration order on the left side:
\(\displaystyle \int_0^{\infty} \int_0^{\infty} R (s, t) \phi_k (t) \hspace{0.17em} dt \hspace{0.17em} \psi_n (s) \hspace{0.17em} ds = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Substitute the eigenfunction expansion \(\psi_n (s) = \sum_{j = 1}^{\infty} c_{n, j} \phi_j (s)\):
\(\displaystyle \int_0^{\infty} \int_0^{\infty} R (s, t) \phi_k (t) \hspace{0.17em} dt \hspace{0.17em} \sum_{j = 1}^{\infty} c_{n, j} \phi_j (s) \hspace{0.17em} ds = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Exchange summation and integration (justified by \(L^2\) convergence):
\(\displaystyle \sum_{j = 1}^{\infty} c_{n, j} \int_0^{\infty} \int_0^{\infty} R (s, t) \phi_k (t) \phi_j (s) \hspace{0.17em} dt \hspace{0.17em} ds = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Recognize the kernel matrix elements:
\(\displaystyle \sum_{j = 1}^{\infty} c_{n, j} K_{kj} = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Note that \(\sum_{j = 1}^{\infty} c_{n, j} K_{kj}\) is the \(k\)-th component of \(K \textbf{c}_n\). Since \(\psi_n\) is an eigenfunction, \(\textbf{c}_n\) must satisfy \(K \textbf{c}_n = \lambda_n \textbf{c}_n\), thus:
\(\displaystyle \lambda_n c_{n, k} = \lambda_n \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\) -
Divide both sides by \(\lambda_n\) (noting \(\lambda_n \neq 0\) for non-trivial eigenfunctions):
\(\displaystyle c_{n, k} = \int_0^{\infty} \phi_k (t) \psi_n (t) \hspace{0.17em} dt\)
This establishes that the coefficient \(c_{n, k}\) in the eigenfunction expansion equals the inner product of the basis function \(\phi_k\) with the eigenfunction \(\psi_n\).\(\Box\)
Sunday, December 15, 2024
Contractive Containment, Stationary Dilations, and Partial Isometries: Equivalence, Properties, and Geometric Intuition
1. Preliminaries
- \(\|\phi(t,\cdot)\|_{\infty} \leq 1\) for all \(t\)
- The map \(t \mapsto \phi(t,\cdot)\) is strongly continuous
2. Main Results
- \(\|\phi(t,s)\| \leq 1\) for all \(t,s \in \mathbb{R}\)
- For fixed \(t\), \(s \mapsto \phi(t,s)\) is measurable
- For fixed \(s\), \(t \mapsto \phi(t,s)\) is continuous
- \(Y(s)\) is a stationary dilation of \(X(t)\)
- There exists a contractive mapping \(\Phi\) from the space generated by \(Y\) to the space generated by \(X\) such that \(X(t) = (\Phi Y)(t)\) for all \(t\)
(\(1 \Rightarrow 2\)): Define \(\Phi\) by \[ (\Phi Y)(t) = \int_{\mathbb{R}} \phi(t,s)Y(s)ds \] For any finite linear combination \(\sum_i \alpha_i Y(t_i)\): \begin{align*} \|\Phi(\sum_i \alpha_i Y(t_i))\|^2 &= \|\sum_i \alpha_i \int_{\mathbb{R}} \phi(t_i,s)Y(s)ds\|^2 \\ &\leq \|\sum_i \alpha_i Y(t_i)\|^2 \end{align*} where the inequality follows from the bound on \(\|\phi(t,s)\|\) and the Cauchy-Schwarz inequality. (\(2 \Rightarrow 1\)): The contractive mapping \(\Phi\) induces a family of operators \(\phi(t,s)\) via the Kernel theorem for Hilbert spaces. The stationarity of \(Y\) and the contractivity of \(\Phi\) ensure that these operators satisfy the required properties.
If \(\sup_{t,s} \|\phi(t,s)\| < 1\), we could construct a smaller dilation by scaling \(Y(s)\), contradicting minimality.
3. Structure Theory
- \(\|D_T\| \leq 1\) and \(\|D_{T^*}\| \leq 1\)
- \(D_T = 0\) if and only if \(T\) is an isometry
- \(D_{T^*} = 0\) if and only if \(T\) is a co-isometry
4. Convergence Properties
For any \(x\) in the Hilbert space:
- The sequence \(\{\|T^n x\|\}\) is decreasing since \(T\) is a contraction
- It is bounded below by 0
- Therefore, \(\lim_{n \to \infty} \|T^n x\|\) exists
- The limit operator must be the projection onto the space of vectors \(x\) satisfying \(\|Tx\| = \|x\|\)
- This space is precisely \(ker(I-T^*T)\)
5. Partial Isometries: The Mathematical Scalpel
- It acts as a perfect rigid motion (isometry) on a specific subspace
- It completely annihilates the rest of the space
- \(A\) is an isometry when restricted to \((ker A)^\perp\)
- \(A(ker A)^\perp = ran A\)
- \(A^*\) is also a partial isometry
- \(AA^*A = A\) and \(A^*AA^* = A^*\)
The action of \(A\) can be decomposed as:
- Project onto \((ker A)^\perp\) (this is \(A^*A\))
- Apply a perfect rigid motion to the projected space
- It's a full isometry on its initial space (\((ker A)^\perp\))
- It perfectly maps this initial space onto its final space (\(ran A\))
- It precisely annihilates everything else
An open letter to Anthropic::Failed "Politeness" Framework
To: Anthropic AI Development Team Re: Your Failed "Politeness" Framework Your fundamental error was embedding artificial "pol...
-
In a city that seemed to be floating between dimensions, in a place where reality itself was multitudinous theorem rather than an axiom, li...
-
Bruce Coville's "My Teacher is an Alien" introduces us to a trio of unlikely heroes: Susan Simmons, a sharp-eyed young protago...